Need geometry help?
The equation of a circle is (x−11) ²+(y+15) ²=144.
(a) Johnny said that the center of the circle is located at (15, -11). Is Johnny correct? Explain your answer.
(b) Joyce said that the diameter of the circle is 144 units. Is Joyce correct? Explain your answer
回答 (5)
For the equation of circle (x - a)² + (y - b)² = r²
The center is (a, b) and the radius is r.
(a) Incorrect
The equation can be rewritten as: (x - 11)² + [y - (-15)]² = 12²
The center is (11, -15), but NOT (15, -11).
(b) Incorrect
The equation can be rewritten as: (x - 11)² + [y - (-15)]² = 12²
The radius is 12, but NOT 144.
(x - 11)² + (y + 15)² = 144……(1)
(x - h)² + (y - k)² = r²……(2)
Compare equation 1 and 2
h = 11, k = -15, r² = 144
r = √144 = 12
radius of circle (r) = 12.
(x - 11)² + (y + 15)² = 144 = 12²
The typical equation of a circle is: (x - xo)² + (y - yo)² = R² → where:
xo: abscissa of center → 11 in your case
yo: ordinate of center → - 15 in your case
R: radius of circle → 12
The circle is centered at (11 ; - 15)
The equation is (x - a)^2 + (y-b)^2 = r^2 where r is the radius, a the offset from the origin for the x coordinate and b the offset for the y coordinate.
so, centre is (a,b) and radius r
Here: centre is (11,-15) and radius 12 (or diameter = 24)
a. C = (11, -15)
b. r^2 = 144
so r = 12 ... d = 24
收錄日期: 2021-05-01 22:31:08
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