Chem Question Please Help?
2019-03-20 8:19 am
What is the activation energy (in kJ) of a reaction whose rate constant increases by a factor of 100 upon increasing the temperature from 300K to 360K?
回答 (1)
2019-03-20 8:49 am
✔ 最佳答案
T₁ = 300 K and T₂ = 360 Kk₁/k₂ = 1/100
R = 8.314 J/(mol K)
Arrhenius equation:
ln(k₁/k₂) = (Eₐ/R) [(1/T₂) - (1/T₁)]
ln(1/100) = (Eₐ/8.314) [(1/360) - (1/300)]
Eₐ = 8.314 ln(1/100) / [(1/360) - (1/300)] J/mol = 68900 J/mol = 68.9 kJ/mol
收錄日期: 2021-05-02 11:21:25
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20190320001925AAXwGCh