how much does 4.97×10^21 molecules of CO2 weigh?
回答 (1)
2019-03-19 11:10 pm
Avogadro constant = 6.022 × 10²³ /mol
Moles of CO₂ = (4.97 × 10²¹ molecules) / (6.022 × 10²³ molecules/mol) = 0.00825 mol
Molar weight of CO₂ = (12.0 + 16.0×2) g/mol = 44.0 g/mol
Weight of CO₂ = (0.00825 mol) × (44.0 g/mol) = 0.363 g
OR:
(4.97 × 10²¹ CO₂ molecules) × (1 mol / 6.022 × 10²³ molecules) × (44 g / 1 mol)
= 0.363 g CO₂
Moles of CO₂ = (4.97 × 10²¹ molecules) / (6.022 × 10²³ molecules/mol) = 0.00825 mol
Molar weight of CO₂ = (12.0 + 16.0×2) g/mol = 44.0 g/mol
Weight of CO₂ = (0.00825 mol) × (44.0 g/mol) = 0.363 g
OR:
(4.97 × 10²¹ CO₂ molecules) × (1 mol / 6.022 × 10²³ molecules) × (44 g / 1 mol)
= 0.363 g CO₂
收錄日期: 2021-05-01 22:26:19
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20190319145357AAuiIk2