How many milliliter of a 2.5 M MgCl2 solution contains 17.5 g MgCl2?
回答 (1)
2019-03-19 10:14 pm
Molar mass of MgCl₂ = (24.3 + 35.5×2) g/mol = 95.3 g/mol
Moles of MgCl₂ = (17.5 g) / (95.3 g/mol) = 0.18363 mol
Volume of MgCl₂ solution = (0.18363 mol) / (2.5 mol/L) = 0.0735 L = 73.5 mL
OR:
(17.5 g MgCl₂) × (1 mol / 95.3 g) × (1000 mL / 2.5 mol) = 73.5 mL MgCl₂ solution
Moles of MgCl₂ = (17.5 g) / (95.3 g/mol) = 0.18363 mol
Volume of MgCl₂ solution = (0.18363 mol) / (2.5 mol/L) = 0.0735 L = 73.5 mL
OR:
(17.5 g MgCl₂) × (1 mol / 95.3 g) × (1000 mL / 2.5 mol) = 73.5 mL MgCl₂ solution
收錄日期: 2021-05-01 22:29:48
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