College Algebra...Quadratic equations...help!?
2019-03-13 8:04 am
Mark hit a golf ball from the ground and its movement follows the equation h(t)= -16t^+88t, where t is the time is seconds and h(t) is the height of the ball at a given time t. Find the time that it took the golf ball to hit the ground again correct to two decimal places. Thank you!
回答 (3)
2019-03-13 8:09 am
h(t) = -16t² + 88t
When the golf ball hits the ground, h(t) = 0
-16t² + 88t = 0
2t² - 11t = 0
(2t - 11)t = 0
t = 5.5 or t = 0 (rejected)
Time taken for the golf ball to hit the group again = 5.50 s (to 2 decimal places)
When the golf ball hits the ground, h(t) = 0
-16t² + 88t = 0
2t² - 11t = 0
(2t - 11)t = 0
t = 5.5 or t = 0 (rejected)
Time taken for the golf ball to hit the group again = 5.50 s (to 2 decimal places)
2019-03-13 8:14 am
DIFFERENTIATE H(T)=-16T^2+88T TO ACHIEVE H'(T)=-32T+88
SOLVE FOR 0 TO FIND THE MAXIMUM
-32T+88=0
-32T=-88
T=88/32=11/4 seconds
THE MAXIMUM OCCURS AT HALF THE TIME, SO NOW LETS DOUBLE THAT BABY
11/4 * 2 = 11/2 = 5.5 seconds
IT TAKES 5.5 SECONDS, JUST LIKE YOU IN BED
SOLVE FOR 0 TO FIND THE MAXIMUM
-32T+88=0
-32T=-88
T=88/32=11/4 seconds
THE MAXIMUM OCCURS AT HALF THE TIME, SO NOW LETS DOUBLE THAT BABY
11/4 * 2 = 11/2 = 5.5 seconds
IT TAKES 5.5 SECONDS, JUST LIKE YOU IN BED
參考: Mathematics PhD
Stanford Mathematics
MIT Math Team
2019-03-13 8:06 am
solve h(t)=0
收錄日期: 2021-05-01 22:29:31
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