高中M2極限 以e表示此式 ！?
回答 (1)
2019-03-12 6:18 pm
Sol
A=lim(x->∞)_[1+1/(2x－1)]^(－2x)
= lim(x->∞)_[1+1/(x－1)]^(－x)
1/A=lim(x->∞)_[1+1/(x－1)]^x
=lim(x->∞)_(1+1/x)^(x+1)
=lim(x->∞)_(1+1/x)^x
=e
A=1/e
A=lim(x->∞)_[1+1/(2x－1)]^(－2x)
= lim(x->∞)_[1+1/(x－1)]^(－x)
1/A=lim(x->∞)_[1+1/(x－1)]^x
=lim(x->∞)_(1+1/x)^(x+1)
=lim(x->∞)_(1+1/x)^x
=e
A=1/e
收錄日期: 2021-04-30 22:41:28
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20190312062320AAFgBmb