Chemistry Question. Please Help?
2019-03-09 1:12 pm
A 25.00 mL solution of sulfuric acid (H2SO4) is titrated to phenolphthalein end point with 27.00 mL of 1.700 M KOH. Calculate the molarity of the acid solution? H2SO4(aq) + 2KOH(aq) → K2SO4(aq) + 2H2O(l)
回答 (1)
2019-03-09 1:57 pm
✔ 最佳答案
H₂SO₄(aq) + 2KOH(aq) → K₂SO₄(aq) + 2H₂O(l)Mole ratio H₂SO₄ : KOH = 1 : 2
Moles of KOH = (1.700 mol/L) × (27.00/1000 L) = 0.0459 mol
Moles of H₂SO₄ = (0.0459 mol) × 1/2 = 0.02295 mol
Molarity of H₂SO₄ = (0.02295 mol) / (25.00/1000 L) = 0.918 M
OR:
(1.700 mol KOH / 1 L KOH) × (27.00/1000 L KOH) × (1 mol H₂SO₄ / 2 mol KOH) / (25.00/1000 L H₂SO₄)
= 0.918 M H₂SO₄
收錄日期: 2021-05-01 22:30:23
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20190309051208AAtXZyr