Chemistry question?
2019-03-08 4:39 pm
Calculate the number of water molecules that you flush down the toilet with each flush if a flush uses 1.5L of water. Remember, for water, 1.0 mL = 1.0 g.
回答 (1)
2019-03-08 4:56 pm
Density of water = 1.00 g/mL
Mass of a flush of water = (1.5 × 1000 mL) × (1.00 g/mL) = 1500 g
Molar mass of water (H₂O) = (16.0 + 1.0×2) = 18.0 g/mol
Number of moles of water in a flush = (1500 g) / (18.0 g/mol) = 83.33 mol
Avogadro constant = 6.022 × 10²³ /mol
Number of water molecules = (83.33 mol) × (6.022 × 10²³ molecules/mol) = 5.02 × 10²⁵ molecules
OR:
(1.5 × 1000 mL) × (1.00 g/mL) × ( 1 mol / 18.0 g) × (6.022 × 10²³ molecules/mol)
= 5.02 × 10²⁵ molecules
Mass of a flush of water = (1.5 × 1000 mL) × (1.00 g/mL) = 1500 g
Molar mass of water (H₂O) = (16.0 + 1.0×2) = 18.0 g/mol
Number of moles of water in a flush = (1500 g) / (18.0 g/mol) = 83.33 mol
Avogadro constant = 6.022 × 10²³ /mol
Number of water molecules = (83.33 mol) × (6.022 × 10²³ molecules/mol) = 5.02 × 10²⁵ molecules
OR:
(1.5 × 1000 mL) × (1.00 g/mL) × ( 1 mol / 18.0 g) × (6.022 × 10²³ molecules/mol)
= 5.02 × 10²⁵ molecules
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