更新1:
0.080 mole 0.80 mole 0.040 mole 0.020 mole 0.40 mole
A solution is 0.20 M barium hydroxide. How many moles of nitric acid must be added to neutralize 100.0 mL of the solution?
回答 (3)
2019-03-05 9:40 am
✔ 最佳答案
Ba(OH)₂ + 2HNO₃ → Ba(NO₃)₂ + 2H₂OMole ratio Ba(OH)₂ : HNO₃ = 1 : 2
No. of moles of Ba(OH)₂ reacted = (0.20 mole/L) × (100.0/1000 L) = 0.020 mole
No. of moles of HNO₃ needed = (0.020 mole) × (2/1) = 0.040 mole
The answer: 0.040 mole
2019-03-05 9:32 am
0.040
2019-03-05 9:32 am
2 * 0.1 * 0.2 = 0.04 mole
收錄日期: 2021-05-01 22:28:38
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