Im not sure how to do this problem: What is the Mass in g of 3.53 moles of glucose (C6H12O6)?
回答 (1)
2019-03-04 9:55 am
Molar mass of C₆H₁₂O₆ (glucose) = (12.0×6 + 1.0×12 + 16.0×6) g/mol = 180.0 g/mol
Mass of C₆H₁₂O₆ = (3.53 mol) × (180.0 g/mol) = 635 g (to 3 sig. fig.)
Mass of C₆H₁₂O₆ = (3.53 mol) × (180.0 g/mol) = 635 g (to 3 sig. fig.)
收錄日期: 2021-05-01 22:28:37
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