How many mols are present in 1.405 Kg of C2H5OH ?
回答 (2)
2019-02-26 8:21 pm
Molar mass of C₂H₅OH = (12.01×2 + 1.008×6 + 16.00) g/mol = 46.07 g/mol
Moles of C₂H₅OH = (1.405 × 1000 g) / (46.07 g/mol) = 30.50 mol
Moles of C₂H₅OH = (1.405 × 1000 g) / (46.07 g/mol) = 30.50 mol
2019-02-27 2:14 pm
(1405 g C2H5OH) / (46.0684 g C2H5OH/mol) = 30.50 mol C2H5OH
收錄日期: 2021-05-02 11:14:30
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https://hk.answers.yahoo.com/question/index?qid=20190226063327AAaFkt1