How many moles in 10kg of ammonium phosphate? -(NH4)3PO4?

2019-02-26 10:25 am

回答 (1)

2019-02-26 10:30 am

✔ 最佳答案

Molar mass of (NH₄)₃PO₄ = (14.0×3 + 1.0×12 + 31.0 + 16.0×4) g/mol = 149.0 g/mol

Moles of (NH₄)₃PO₄ = (10 × 1000 g) / (149.0 g/mol) = 67.1 mol

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