A 5.00g mass of a metal was heated to 100.0C and then plunged into a 100.0g of water at 14.0C. The temperature of the resulting mixture became 28.0C.
How many joules of heat did the water absorb?
How many joules did the metal lose?
What is the heat capacity of the metal sample? (J/C)
What is the specific heat of the metal? (J/gC)
Help me with thermochemistry?
2019-02-20 2:08 pm
回答 (1)
2019-02-20 2:29 pm
✔ 最佳答案
Heat change = m c ΔTHeat absorbed by the water
= (100.0 g) × [4.186 J/(g °C)] × [(28.0 - 14.0) °C]
= 5860 J
Heat lost by the metal
= Heat absorbed by the water
= 5860 J
Heat capacity of the metal sample
= (5860 J) / [(100.0 - 28.0) °C]
= 81.4 J/°C
Specific heat of the metal
= (81.4 J/°C) / (5.00 g)
= 16.3 J/g°C
(The value may be too large.)
收錄日期: 2021-04-24 07:40:50
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