✔ 最佳答案
It's not so much a typo, as an omission.
The volume of the 0.3M solution has been omitted. To find the mass of the solute we would need to know the volume of the 0.3M solution.
For instance, "How many grams of NaCl are needed to prepare 500 mL of a 0.3 M stock solution?"
0.5L x (0.3 mol NaCl / 1L) x (58.5g NaCl / 1 mol NaCl) = 9g NaCl