Ammonia gas occupies a volume of 57.9 L at a pressure of 532.4 atm. If the pressure were lowered to 256.8 atm, what would the new volume be?
回答 (1)
2019-02-20 12:34 am
Initial: P₁ = 532.4 atm, V₁ = 57.9 L
New: P₂ = 256.8 atm, V₂ = ? L
According to Boyle's law: P₁V₁ = P₂V₂
Hence, V₂ = V₁ × (P₁/P₂)
The original pressure, V₂ = (57.9 L) × (542.4/256.8) = 120 L
New: P₂ = 256.8 atm, V₂ = ? L
According to Boyle's law: P₁V₁ = P₂V₂
Hence, V₂ = V₁ × (P₁/P₂)
The original pressure, V₂ = (57.9 L) × (542.4/256.8) = 120 L
收錄日期: 2021-05-01 22:28:49
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20190219162637AA2fsiz