Ammonia gas occupies a volume of 57.9 L at a pressure of 532.4 atm. If the pressure were lowered to 256.8 atm, what would the new volume be?

Initial: P₁ = 532.4 atm, V₁ = 57.9 L
New: P₂ = 256.8 atm, V₂ = ? L

According to Boyle's law: P₁V₁ = P₂V₂
Hence, V₂ = V₁ × (P₁/P₂)

The original pressure, V₂ = (57.9 L) × (542.4/256.8) = 120 L