Can someone help me with this geometry problem?
回答 (4)
2019-02-19 11:45 pm
AB = AC (tangents from a point)
AB = BC (given)
Hence, AB = BC = AC
∠ABC = 60° (int. ∠ of equilateral Δ)
x = ∠ABC = 60° (∠s in alt. segment)
AB = BC (given)
Hence, AB = BC = AC
∠ABC = 60° (int. ∠ of equilateral Δ)
x = ∠ABC = 60° (∠s in alt. segment)
2019-02-19 11:48 pm
From the diagram, <BCA=<ABC=<BAC=x
=>
x=60*
=>
x=60*
2019-02-19 10:58 pm
That a piece of pish it’s 60
2019-02-20 2:56 am
x = 60 degrees
收錄日期: 2021-05-02 11:14:10
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