Can someone help me with this geometry problem?

AB = AC (tangents from a point)
AB = BC (given)
Hence, AB = BC = AC
∠ABC = 60° (int. ∠ of equilateral Δ)

x = ∠ABC = 60° (∠s in alt. segment)

From the diagram, <BCA=<ABC=<BAC=x
=>
x=60*

That a piece of pish it’s 60

x = 60 degrees