a. 3(cos 0° + i sin 0°)
b. 3(cos 90° + i sin 90°)
c. 3(cos 180° + i sin 180°)
d.3(cos 270° + i sin 270°)
Express the complex number in trigonometric form. 3 Please help I do not understand what this is asking?
2019-01-29 4:38 am
回答 (2)
2019-01-29 4:48 am
e^(ix) = cos x + i sin x
use radians
a. 3(cos 0° + i sin 0°) = 3e^(i0)
b. 3(cos 90° + i sin 90°) = 3 e^(ipi/2)
c. 3(cos 180° + i sin 180°) = 3 e^(pi)
d.3(cos 270° + i sin 270°) = 3 e^(3pi/2)
use radians
a. 3(cos 0° + i sin 0°) = 3e^(i0)
b. 3(cos 90° + i sin 90°) = 3 e^(ipi/2)
c. 3(cos 180° + i sin 180°) = 3 e^(pi)
d.3(cos 270° + i sin 270°) = 3 e^(3pi/2)
2019-01-29 4:47 am
I take it that the number is 3?
z = 3
z = 3 + 0i
z = 3 * (1 + 0i)
cos(t) = 1
sin(t) = 0
t = 0 degrees
z = 3 * (cos(0) + i * sin(0))
That's all there is to it.
z = 3
z = 3 + 0i
z = 3 * (1 + 0i)
cos(t) = 1
sin(t) = 0
t = 0 degrees
z = 3 * (cos(0) + i * sin(0))
That's all there is to it.
收錄日期: 2021-05-01 22:17:27
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20190128203823AAGqXlV