更新1:
我在做功課時看到這題"設 f(x)=4x^(2)+6x-4。 如果g(x-2)=f(x), 找g(x)",本來想說可以完成,結果發現老師沒有教過,連書及筆記也沒有例子,求解!!!急!!!!
我在做功課時看到這題"設 f(x)=4x^(2)+6x-4。 如果g(x-2)=f(x), 找g(x)",本來想說可以完成,結果發現老師沒有教過,連書及筆記也沒有例子,求解!!!急!!!!?
回答 (4)
2019-01-06 12:01 am
let y = x-2
=> x = y+2 ....(1)
g(y) = g(x-2) = f(x) = 4x*x + 6x - 4
substitute (1)
g(y) = 4*(y+2)*(y+2) + 6(y+2) - 4
= 4yy + 16y + 16 + 6y + 12 - 4
= 4yy + 22y + 24
=> x = y+2 ....(1)
g(y) = g(x-2) = f(x) = 4x*x + 6x - 4
substitute (1)
g(y) = 4*(y+2)*(y+2) + 6(y+2) - 4
= 4yy + 16y + 16 + 6y + 12 - 4
= 4yy + 22y + 24
2019-01-05 9:57 pm
簡單說.他求g(x).這個g(x)式子帶入X-2時.就會等於4X平方+6X-4也就是f(x).反推回去.g(x)式子就等於f(x+2)反推回去..帶數字時別帶錯喔
2019-01-06 2:40 pm
let y = x-2
=> x = y+2 ....(1)
g(y) = g(x-2) = f(x) = 4x*x + 6x - 4
substitute (1)
g(y) = 4*(y+2)*(y+2) + 6(y+2) - 4
= 4yy + 16y + 16 + 6y + 12 - 4
= 4yy + 22y + 24
=> x = y+2 ....(1)
g(y) = g(x-2) = f(x) = 4x*x + 6x - 4
substitute (1)
g(y) = 4*(y+2)*(y+2) + 6(y+2) - 4
= 4yy + 16y + 16 + 6y + 12 - 4
= 4yy + 22y + 24
2019-01-05 9:48 pm
免費例題教學影片，
https://youtu.be/mxk0ANVFHsE
https://www.khanacademy.org/math/algebra2/polynomial-functions/finding-zeros-of-polynomials/v/finding-roots-or-zeros-of-polynomial-example
https://www.khanacademy.org/math/algebra-home/alg-functions/alg-determining-the-range-of-a-function/v/domain-and-range-of-a-function-given-a-formula
https://www.mathway.com/popular-problems/Finite%20Math/610637
https://youtu.be/mxk0ANVFHsE
https://www.khanacademy.org/math/algebra2/polynomial-functions/finding-zeros-of-polynomials/v/finding-roots-or-zeros-of-polynomial-example
https://www.khanacademy.org/math/algebra-home/alg-functions/alg-determining-the-range-of-a-function/v/domain-and-range-of-a-function-given-a-formula
https://www.mathway.com/popular-problems/Finite%20Math/610637
收錄日期: 2021-05-03 04:35:24
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20190105134254AAi06j9