Physics question?
2018-11-27 3:10 am
In the equation F=m⋅v2rF=m⋅v2r find the value of m when F = 590, v = 34, and r = 17.
回答 (3)
2018-11-27 3:31 am
F = m*ac = m*V^2/r
m = F*r/(V^2) = 590*17/34^2 = 8.68 kg
m = F*r/(V^2) = 590*17/34^2 = 8.68 kg
2018-11-28 7:20 pm
Given,
Force (F) = 590 N
Velocity (V) = 34 m/sec²
Radius (r) = 17m
We know that:-
Force (F) = mv² / r
→ (F x r) = mv²
→ mass (m) = (F x r) / v² = 590 N x 17M / (34 m/sec)²
= 10030 / 1156 = 8.67 kg
∴ mass (m) = 8.67 kg.
Force (F) = 590 N
Velocity (V) = 34 m/sec²
Radius (r) = 17m
We know that:-
Force (F) = mv² / r
→ (F x r) = mv²
→ mass (m) = (F x r) / v² = 590 N x 17M / (34 m/sec)²
= 10030 / 1156 = 8.67 kg
∴ mass (m) = 8.67 kg.
2018-11-27 3:46 am
F = (mv^2)/r
Fr = mv^2
m = Fr/v^2
= (590 * 17)/34^2
= 8.676470588
= 8.68 kg (2 dp)
Fr = mv^2
m = Fr/v^2
= (590 * 17)/34^2
= 8.676470588
= 8.68 kg (2 dp)
收錄日期: 2021-05-01 22:27:09
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