What mass of H2(g) is produced from the reaction of 1.5 g Al(s) with excess hydrochloric acid?
回答 (1)
2018-11-27 3:37 am
2 Al + 6 HCl → 2 AlCl3 + 3 H2
(1.5 g Al) / (26.98154 g Al/mol) x (3 mol H2 / 2 mol Al) x (2.01588 g H2/mol) = 0.17 g H2
(1.5 g Al) / (26.98154 g Al/mol) x (3 mol H2 / 2 mol Al) x (2.01588 g H2/mol) = 0.17 g H2
收錄日期: 2021-05-01 22:00:06
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