Find ΔE° (kJ) for the reaction below if the process is carried out at a constant pressure of 1.00 atm and ΔV (the volume change) = -24.5 L. (1 L ∙ atm = 101 J)
2 CO(g) + O2 (g) → 2 CO2(g) ΔH° = -566. kJ
Find ΔE° (kJ) for the reaction below if the process is carried out at a constant pressure?
2018-11-24 4:59 am
回答 (1)
2018-11-24 5:41 am
✔ 最佳答案
w = (1.00 atm) x (24.5 L) x (101 J/L∙atm) = 2474.5 J = 2.47 kJ(Since the volume decreased, work was done on the system, so the value for w is positive.)
To find ΔE° add the positive work to ΔH°, which is the heat:
-566. kJ + 2.47 kJ = -564 kJ
收錄日期: 2021-04-24 01:12:48
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