1.試求sin10°sec80°+tan40°tan50°之值
2.求1/sin^2A+1/csc^2A之值
3.試求1/cot^2A-1/cos^2A之值
高職三角函數求大神分析過程?
2018-10-26 7:16 pm
回答 (1)
2018-10-26 8:10 pm
✔ 最佳答案
1.試求Sin10°Sec80°+Tan40°Tan50°之值 Sol
Sin10°Sec80°+Tan40°Tan50°
=Sin10°/Cos80°+Tan40°/Cot50°
=Sin10°/Sin10°+Tan40°/Tan40°
=2
2.求1/Sin^2 A+1/Csc^2 A之值
Sol
1/Sin^2 A+1/Csc^2 A
=1/Sin^2 A+Sin^2 A
=(1+Sin^4 A)/Sin^2 A
3.試求1/Cot^2 A-1/Cos^2 A之值
Sol
1/Cot^2 A-1/cCs^2 A
=Sin^2 A/Cos^2 A－1/Cos^2 A
=－Cos^2 A/Cos^2 A
=－1
收錄日期: 2021-04-30 22:47:11
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