Quadratic equation?
2018-10-18 10:03 am
Find the complex number z such that (1+4i)z is a real number and z +6-i is an imaginary number.
回答 (2)
2018-10-18 12:39 pm
✔ 最佳答案
find the complex number z such that (1－4i)z is a real number and z+6-i is an imaginary number.Sol
設z=a(1+4i)，a∈R
(1－4i)z
=a(1－4i)(1+4i)
=17a
z+6－i
=a(1+4i)+6－i
=(a+6)+(4a－1)i
a+6=0
a=－6
z=－6－24i
2018-10-18 11:56 am
(1+4i)z=實數
z=(1-4i).............(1)
z+6-i=純虛數
設x是不等於1的數
xi-6=z...........(2)
x=-7i-4
z=(1-4i).............(1)
z+6-i=純虛數
設x是不等於1的數
xi-6=z...........(2)
x=-7i-4
收錄日期: 2021-04-18 18:10:14
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https://hk.answers.yahoo.com/question/index?qid=20181018020331AAIBUSK