Adult tickets cost $8 and student tickets cost $5. She sold 35 more student tickets than adult tickets. total of $1475. how many of each?
回答 (2)
2018-10-01 4:42 am
We can solve this intuitively without resorting to algebra:
Take the 35 extras student tickets ($5 × 35 = $175) and subtract them from the total. That leaves $1300.
Now we have equal numbers of students and adults buying pairs of tickets (one each of a $5 and $8). That's $13, so we must have 100 adults and 100 students.
$1300/$13 = 100 pairs
Add back the 35 extras student tickets and we have 135 students.
Answer:
100 adults
135 students
Take the 35 extras student tickets ($5 × 35 = $175) and subtract them from the total. That leaves $1300.
Now we have equal numbers of students and adults buying pairs of tickets (one each of a $5 and $8). That's $13, so we must have 100 adults and 100 students.
$1300/$13 = 100 pairs
Add back the 35 extras student tickets and we have 135 students.
Answer:
100 adults
135 students
2018-10-01 4:07 am
Let adults tickets sold = x
the students tickets sold will be = x+35
Total cost = 8x + 5(x+35)
1475 = 8x + 5(x+35)
1475 = 8x + 5x + 175
13x = 1300
x = 100
She sold 100 adult tickets and 135 student tickets
the students tickets sold will be = x+35
Total cost = 8x + 5(x+35)
1475 = 8x + 5(x+35)
1475 = 8x + 5x + 175
13x = 1300
x = 100
She sold 100 adult tickets and 135 student tickets
收錄日期: 2021-05-01 00:18:36
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