中二程度Maths!!急!?
回答 (1)
2018-08-21 6:00 am
3(a+b)+(c－4)(a+b)
=(a+b)*[3+(c－4)]
=(a+b)(c－1)
=(a+b)*[3+(c－4)]
=(a+b)(c－1)
2018-09-20 4:49 pm
3(a+b)+(c-4)(a+b)
=3a+3b+ac.+bc-4a-4b
=-(a+b)+c(a+b)
=(c-1)(a+b)
=3a+3b+ac.+bc-4a-4b
=-(a+b)+c(a+b)
=(c-1)(a+b)
收錄日期: 2021-04-24 01:12:45
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20180820142201AA4ZQIE