You are given 410.0 mL of a 1.581 M K2CO3 solution. There are ______ moles of K+ present in the solution?

The answer:
You are given 410.0 mL of a 1.581 M K₂CO₃ solution. There are __1.296__ moles of K⁺ present in the solution.

Work:
No. of moles of K₂CO₃ = (1.581 mol/L) × (410.0/1000 L) = 0.6482 mol
According to the formula of K₂CO₃, each mole of K₂CO₃ contains 2 moles of K⁺.
No. of moles of K⁺ = (0.6482 mol) × 2 = 1.296 mol

OR:
(1.581 mol K₂CO₃ / 1 L solution) × (410.0/1000 L solution) × (2 mol K⁺ / 1 mol K₂CO₃)
= 1.296 mol K⁺