Geometry help!!!?
回答 (2)
2018-07-25 8:56 am
Let (x, y) be the mid-point of FJ.
F(x₁, y₁) = F(-5, -3)
J(x₂, y₂) = J(7, -1)
x = (x₁ + x₂)/2 = [(-5) + 7]/2 = 1
y = (y₁ + y₂)/2 = [(-3) + (-1)]/2 = -2
The answer: (1. -2)
F(x₁, y₁) = F(-5, -3)
J(x₂, y₂) = J(7, -1)
x = (x₁ + x₂)/2 = [(-5) + 7]/2 = 1
y = (y₁ + y₂)/2 = [(-3) + (-1)]/2 = -2
The answer: (1. -2)
2018-07-25 8:11 pm
The midpoint is at (-1, 2)
收錄日期: 2021-05-01 22:26:24
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