M=4Pcosx+4Psinx __(1) dM/dx=4P(cosx-sinx)=0 ___(2) tanx=1 (1)如何推導出(2)?
回答 (2)
2018-07-16 6:25 pm
4P(Cosx－Sinx)=0
P<>0
Cosx－Sinx=0
Cosx=Sinx
Tanx=Sinx/Cosx=1
P<>0
Cosx－Sinx=0
Cosx=Sinx
Tanx=Sinx/Cosx=1
2018-07-18 8:01 pm
M=4Pcosx+4Psinx __(1)
dM/dx=4P(cosx-sinx)=0 ___(2) t
(1)如何推導出(2)?
dM/dx=4P(cosx-sinx)=0 ___(2) t
(1)如何推導出(2)?
收錄日期: 2021-04-30 22:38:15
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https://hk.answers.yahoo.com/question/index?qid=20180716102107AA9gtrq