To what volume should you dilute 15 mL of a 12 M stock HCl solution to obtain a 0.540 M HCl solution?

Initial: C₁ = 12 M, V₁ = 15 mL,
Final: C₂ = 0.540 M, V₂ = ? mL

For dilution of solution: C₁ V₁ = C₂ V₂
Final volume, V₂ = V₁ × (C₁/C₂) = (15 mL) × (12/0.540) = 333 mL