solve the following: 27a-9b+3c-8=0 8a-4b+2c-8=0 -a-b-c-8=0 Find a,b,c?

27a - 9b + 3c - 8 = 0 …… [1]
8a - 4b + 2c - 8 = 0 …… [2]
-a - b - c - 8 = 0 …… [3]

[1]*2:
54a - 18b + 6c = 16 …… [4]

[2]*3:
24a - 12b + 6c = 24 …… [5]

[3]*6:
-6a - 6b - 6c = 48 …… [6]

[4]+[6]:
48a - 24b = 64
6a - 3b = 8 …… [7]

[5] + [6]:
18a - 18b = 72
a - b = 4 ……. [8]
3a - 3b = 12 …… [9]

[7] + [9]:
3a = -4
a = -4/3

Substitute a = -4/3 into [8]:
(-4/3) - b = 4
b = -16/3

Substitute a = -4/3 and b = -16/3 into [3] :
-(-4/3) - (-16/3) - c - 8 = 0
c = -4/3

Hence, (a, b, c) = (-4/3, -16/3, -4/3)

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Check:
27a - 9b + 3c - 8 = 27(-4/3) - 9(-16/3) + 3(-4/3) - 8 = 0 …… (True)
8a - 4b + 2c - 8 = 8(-4/3) - 4(-16/3) + 2(-4/3) - 8 = 0 …… (True)
-a - b - c - 8 = -(-4/3) - (-16/3) - (-4/3) - 8 = 0 …… (True)

Hence, (a, b, c) = (-4/3, -16/3, -4/3)

27a - 9b + 3c - 8 = 0
8a - 4b + 2c - 8 = 0
-a - b - c - 8 = 0
Solution:
a = -4/3, b = -16/3, c = -4/3

27a - 9b + 3c = 8

8a - 4b + 2c = 8
-2a - 2b - 2c = 16------------add

6a - 6b = 24

54a - 18b + 6c = 16
-6a - 6b - 6c = 48----------add

48a - 24b = 64

6a - 6b = 24
48a - 24b = 64

24a - 24b = 96
48a - 24b = 64________subtract

-24a = 32
a = - 4/3

6a - 6b = 24
- 8 - 6b = 24
- 32 = 6b
b = - 16/3

- a - b - c = 8
4/3 + 16/3 - c = 8
20/3 - 24/3 = c
c = - 4/3

a = - 4/3. b = -16/3 , c = - 4/3

27a - 9b + 3c - 8 = 0
8a - 4b + 2c - 8 = 0
-a - b - c - 8 = 0
Solution:
a = -4/3, b = -16/3, c = -4/3