Can pb2+ react with k2CrO4 and form precipitate ? Is it related to standard reduction potential ? thank you^^?

Equation for the precipitate reaction:
Pb²⁺(aq) + K₂Cr₂O₇(aq) → PbCr₂O₇(s) + 2K⁺(aq)

In the reaction, the oxidation number of K, Pb, Cr and O are +1, +2, +7 and -2 respectively, and thus the reaction is NOT redox. As there is no oxidation or reduction, the reaction is NOT related to standard reduction potential.

Pb{2+} + K2CrO4 → PbCrO4(s) + 2 K{+}

What matters when predicting precipitates is the solubility of the proposed product. In this case lead (II) chromate is insoluble, so it precipitates.