Please help, thank you in advance?
2018-07-09 2:49 pm
A grasshopper jumps at a 65.0 degrees angle at 5.42 m/s. At what time does it reach its maximum height?
回答 (2)
2018-07-09 3:29 pm
Take g = 9.81 m/s²
Take all upward quantities to be positive.
Consider the vertical motion (uniform acceleration motion):
Initial velocity, vₒ = 5.42 sin65.0° m/s
Final velocity, v = 0 m/s
Acceleration, a = -9.81 m/s²
v = vₒ + at
Time taken, t = (v - vₒ) / a = [0 - (5.42 sin65.0°)] / 9.81 = 0.5 s
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Take all upward quantities to be positive.
Consider the vertical motion (uniform acceleration motion):
Initial velocity, vₒ = 5.42 sin65.0° m/s
Final velocity, v = 0 m/s
Acceleration, a = -9.81 m/s²
v = vₒ + at
Time taken, t = (v - vₒ) / a = [0 - (5.42 sin65.0°)] / 9.81 = 0.5 s
_
2018-07-09 4:17 pm
About 4 PM I think.
Ar ar ar ar ..... But seriously....
Vy = Uy - gT = 0 at max height; so T = (U sin(65))/9.8 = (5.42*sin(radians(65)))/9.8 = .5 seconds. ANS.
Ar ar ar ar ..... But seriously....
Vy = Uy - gT = 0 at max height; so T = (U sin(65))/9.8 = (5.42*sin(radians(65)))/9.8 = .5 seconds. ANS.
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