If the exterior angles or a convex octagon are x+15,3x-1,2x+10,2x+15,2x-20,3x-4,3x-11 and 6x.?

Sum of exterior angles of a convex polygon = 360°
(x + 15) + (3x - 1) + (2x + 10) + (2x + 15) + (2x - 20) + (3x - 4) + (3x - 11) + 6x = 360
x + 15 + 3x - 1 + 2x + 10 + 2x + 15 + 2x - 20 + 3x - 4 + 3x - 11 + 6x = 360
22x + 4 = 360
22x = 356
x = 178/11

The largest of the angles = 6x° = 6 * (178/11)° = (1068/11)° = (97 1/11)°