Math Help Please?

2018-07-09 6:22 am
Each of 2 balls is painted either red or blue and then placed in an urn. suppose that each ball is colored blue with probability 1/2 & that these events are independent.

A) suppose that you know that red paint has been used (and so at least 1 of the balls is painted red). Compute the conditional probability that both balls are red.
更新1:

B) now suppose that the urn falls and 1 ball falls out. It's painted red. What's the probability that both balls are red in this case?

回答 (3)

2018-07-09 6:34 am
✔ 最佳答案
Part A:

There are 3 possible outcomes that result in at least one red ball:
{RR, RB, BR}

Only one of the conditional outcomes has two red balls {RR}, so the probability is 1/3.

Answer - part a:
1/3

UPDATE:

Part B:

There are 4 ways you could have gotten to the case where a red ball rolls out of the urn.
1) RB and the first (red) ball rolls out.
2) BR and the second (red) ball rolls out.
3) RR and the first (red) ball rolls out.
4) RR and the second (red) ball rolls out.

That's 2 ways out of 4. So the probability of the second scenario is 1/2 (not 1/3).

Answer - part b:
1/2
2018-07-09 7:29 am
1/3
2018-07-09 7:00 am
Don't rephrase when you can't solve the them. By doing so you change the meaning of the original question.

Your English is bad in terms of this question.


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