how many grams of cuso4 are needed to make 350 ml of a solution that contains 10.5 mg/ml of cu2+ ion?
回答 (2)
2018-07-08 7:09 pm
Mass of 1 mole of CuSO₄ = (63.5 + 32.1 + 16.0×4) g = 159.6 g
Mass of Cu²⁺ ion in 1 mole of CuSO₄ = 63.5 g
Mass fraction of Cu²⁺ ion in CuSO₄ = 63.5/159.6
Mass of Cu²⁺ ion in the solution = (10.5 mg/ml) × (350 ml) × (1 g / 1000 mg) = 3.675 g
Mass of CuSO₄ needed = (3.675 g) × (159.6/63.5) = 9.24 g (to 3 sig. fig.)
Mass of Cu²⁺ ion in 1 mole of CuSO₄ = 63.5 g
Mass fraction of Cu²⁺ ion in CuSO₄ = 63.5/159.6
Mass of Cu²⁺ ion in the solution = (10.5 mg/ml) × (350 ml) × (1 g / 1000 mg) = 3.675 g
Mass of CuSO₄ needed = (3.675 g) × (159.6/63.5) = 9.24 g (to 3 sig. fig.)
2018-07-08 10:39 pm
(10.5 x 10^-3 g Cu/mL) x (350 mL) / (63.5463 g Cu/mol) x (1 mol CuSO4 / 1 mol Cu) x (159.6086 g CuSO4/mol) =
9.23 g CuSO4
9.23 g CuSO4
收錄日期: 2021-04-24 01:06:03
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