Math Help Please?
2018-07-07 7:15 am
An urn contains 1 red and 2 blue balls. Balls are drawn from the urn successively, at random and with replacement. What's the probability that exactly 3 blues occur in the first 5 trials?
回答 (5)
2018-07-07 7:36 am
n=5
r=3
p=2/3 = 0.6667
P = 5C3*0.6667^3*0.3333^2
= 0.3292
r=3
p=2/3 = 0.6667
P = 5C3*0.6667^3*0.3333^2
= 0.3292
2018-07-07 7:22 am
With replacement, each draw has a 2 in 3 chance of drawing a blue. The odds for five trials are:
(2/3)(2/3)(2/3)(2/3)(2/3) or 32/243
(2/3)(2/3)(2/3)(2/3)(2/3) or 32/243
2018-07-07 8:08 pm
For five trials: 2/3*2/3*2/3*1/3*1/3 = 8/243
2018-07-07 8:00 am
10*(2/3)^3(1/3)^2 = 80/243
2018-07-07 7:24 am
X~Bi(n=5,p=2/3
Pr(X=3) = ... plug in formula of Binomial
Pr(X=3) = ... plug in formula of Binomial
收錄日期: 2021-04-24 01:07:24
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20180706231524AAhaBmz