what is the apparent mass of a 5.9x10^3 kg alien spacecraft traveling at 0.84c?
回答 (3)
2018-06-26 6:08 pm
Apparent mass, m
= mₒ / √[1 - (v/c)²]
= (5.9 × 10³) / √[1 - (0.84c/c)²] kg
= 1.1 × 10⁴ kg
The answer: 1.1 × 10⁴ kg
= mₒ / √[1 - (v/c)²]
= (5.9 × 10³) / √[1 - (0.84c/c)²] kg
= 1.1 × 10⁴ kg
The answer: 1.1 × 10⁴ kg
2018-06-27 1:57 am
Ma = Apparent mass
Mr = Real mass
Mr=λMa
λ = 1 / (1 - (v/c)^2)) - > 1/(1-(0.84)^2))
λ = 2.77
so 5.9X10^3kg / 2.77 = 2.2x10^4kg ( rounded up from 2.129x10^4 kg )
Mr = Real mass
Mr=λMa
λ = 1 / (1 - (v/c)^2)) - > 1/(1-(0.84)^2))
λ = 2.77
so 5.9X10^3kg / 2.77 = 2.2x10^4kg ( rounded up from 2.129x10^4 kg )
2018-06-26 2:06 pm
7.5 centrons
收錄日期: 2021-04-24 01:04:13
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https://hk.answers.yahoo.com/question/index?qid=20180626060137AAhwn3K