futhermore, what is the pH of the solution?
what is the OH- concentration in the solution?
The molarity of an aqueous solution of LiOH is 0.0025 M. - what is the concentration of H3O+ in this solution?
2018-06-07 9:48 pm
回答 (2)
2018-06-07 10:06 pm
LiOH is a strong base which completely dissociates in water to give OH⁻ ions.
[OH⁻] = [LiOH]ₒ = 0.0025 M
[H₃O⁺] = Kw / [OH⁻] = (1.0 × 10⁻¹⁴) / 0.0025 M = 4.0 × 10⁻¹² M
pH = -log[H₃O⁺] = -log(4.0 × 10⁻¹²) = 11.4
[OH⁻] = [LiOH]ₒ = 0.0025 M
[H₃O⁺] = Kw / [OH⁻] = (1.0 × 10⁻¹⁴) / 0.0025 M = 4.0 × 10⁻¹² M
pH = -log[H₃O⁺] = -log(4.0 × 10⁻¹²) = 11.4
2018-06-07 10:07 pm
LiOH is a very strong base that totally dissociates so a 2.5 x 10^-3 M LiOH solution has [OH-] of 2.5 x 10^-3. This means the pOH = -log (2.5 x 10^-3) = 2.6; pH = 14.0-pOH so pH = 14.0-2.6 = 11.4 and 10^-pH = [H+] = 10^-11.4 = 3.7x10^-10
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