three times some number equals seventy-eight more than the number itself?

2018-06-07 10:23 am

回答 (18)

2018-06-07 10:25 am
Let n be the number.

3n - n = 78
2n = 78
n = 39

The number is 39.
2018-06-07 12:07 pm
Three times some number equals seventy-eight more than the number itself.
Two times some number equals seventy-eight.
The number is thirty-nine.
2018-06-07 10:32 am
2x = 78
x = 39
2018-06-09 5:24 am
Let that number be x, if you want to find it, then write
3x=x+78=>
2x=78=>
x=39
2018-06-07 11:14 pm
3x = x + 78
2x = 78
x = 39.
2018-06-07 9:40 pm
Using algebra the value of the number is 39
2018-06-07 9:26 pm
half of 78
2018-06-07 7:41 pm
3x = x + 78
2x = 78
x = 39
2018-06-07 5:02 pm
39
2018-06-07 4:45 pm
Call the number x.

You can write the equation as you read through the question:

Three times some number ....3x
equals ....=
seventy-eight more than the number itself .... x + 78

Put it together:
3x = x + 78
2x = 78
x = 39
2018-06-07 4:15 pm
3X=78+X
-X=78-X
2X=78
X=39
2018-06-07 2:34 pm
Let x be the unknown number:

3x = x + 78 ===> Solve for x ===> 3x - x = 78 ===> 2x = 78 ===> x = 78/2 = 39 (ANSWER).
2018-06-07 11:44 am
3n = n+78
2n = 78
n = 39
2018-06-07 11:38 am
X=39...equation: 3X=X+78; proof 3(39) =39 + 78 ???

117=117, so correct answer is THIRTY NINE
2018-06-07 10:53 am
Three times some number equals seventy-eight more than the number itself ---> 3x=78+x
solve for x
2018-06-07 10:31 am
3x = x + 78
2x = 78
x = 39
2018-06-07 10:25 am
Let n = the number. So you have

3*n = n + 78
3*n - n = 2n = 78 --> n = 78/2 = 39
2018-06-07 10:24 am
Let the number be x
3x=x+78
2x=78
x=39
The number is 39


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