three times some number equals seventy-eight more than the number itself?

Let n be the number.

3n - n = 78
2n = 78
n = 39

The number is 39.

Three times some number equals seventy-eight more than the number itself.
Two times some number equals seventy-eight.
The number is thirty-nine.

2x = 78
x = 39

Let that number be x, if you want to find it, then write
3x=x+78=>
2x=78=>
x=39

3x = x + 78
2x = 78
x = 39.

Using algebra the value of the number is 39

half of 78

3x = x + 78
2x = 78
x = 39

39

Call the number x.

You can write the equation as you read through the question:

Three times some number ....3x
equals ....=
seventy-eight more than the number itself .... x + 78

Put it together:
3x = x + 78
2x = 78
x = 39

3X=78+X
-X=78-X
2X=78
X=39

Let x be the unknown number:

3x = x + 78 ===> Solve for x ===> 3x - x = 78 ===> 2x = 78 ===> x = 78/2 = 39 (ANSWER).

3n = n+78
2n = 78
n = 39

X=39...equation: 3X=X+78; proof 3(39) =39 + 78 ???

117=117, so correct answer is THIRTY NINE

Three times some number equals seventy-eight more than the number itself ---> 3x=78+x
solve for x

3x = x + 78
2x = 78
x = 39

Let n = the number. So you have

3*n = n + 78
3*n - n = 2n = 78 --> n = 78/2 = 39

Let the number be x
3x=x+78
2x=78
x=39
The number is 39