Please help with chemistry homework! Will rate well for a correct answer :)?

(a)
X + Y → Z
Rate = k [X]ˣ [Y]ʸ

The 2nd set of data: 0.127 = k (0.20)ˣ (0.30)ʸ …… [1]
The 3rd set of data: 1.02 = k (0.40)ˣ (0.60)ʸ …… [2]
The 4th set of data: 0.254 = k (0.20)ˣ (0.60)ʸ …… [3]

[2]/[3] :
4 = 2ˣ
2ˣ = 2²
x = 2

[3]/[1] :
2 = 2ʸ
2ʸ = 2¹
y = 1

Rate = k [X]² [Y]
Overall order of reaction = 2 + 1 = 3


(b)
Rate = k [X]² [Y]

The 5th set of data :
0.509 = k (0.40)² (0.30)
k = 10.6 /(M² s)
Rate = 10.6 [X]² [Y]

When [X] = 0.30 M and [Y] = 0.40 M:
Rate = 10.6 (0.30)² (0.40) M/s = 0.382 M/s

Look at the second and fifth trials. [Y] is the same, and [X] is doubled. The rate quadruples. Therefore, the rate is proportional to the square of [X].

Now, look at the second and fourth trials. This time, [X] is the same, and [Y] is doubled. The rate also doubles. Therefore, the rate is proportional [Y].

rate = k [X]² [Y]

Overall, this is a third order reaction.

Using any of the data points, we can estimate k:
0.053 = k (0.10)² (0.50)
k = 10.6

rate = 10.6 (0.30)² (0.40)
rate = 0.382 M/s