how many grams are there in 2.30x10^24 atoms of silver?

2018-05-31 3:35 pm
更新1:

How many grams are there in 2.30x10^24 atoms of silver? I have forgotten how to do this problem. I know I'm to use avogardro's number but don't know how to put the problem together.

回答 (1)

2018-05-31 3:48 pm
1 mole of atoms is equivalent to 6.022 × 10²³ atoms.
No. of moles of Ag atoms = (2.30 × 10²⁴ atoms) / (6.022 × 10²³ atoms/mol) = 3.82 mol

Molar mass of Ag = 107.9 g/mol
Mass of Ag = (3.82 mol) × (107.9 g/mol) = 412 g (to 3 sig. fig.)


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