Chemistry Question!!?

2018-05-25 12:33 pm
N2(g) + 3H2(g) → 2 NH3(g), if someone keeps adding more and
more hydrogen gas to an excess of nitrogen, what will happen to
the amount of ammonia produced?
更新1:

If that reaction took place in a large balloon and was allowed to reach equilibrium, what would happen if someone squeezed the balloon into a smaller volume?

回答 (2)

2018-05-25 8:16 pm
The reaction is reversible. The equation should be:
N₂(g) + 3H₂(g) ⇌ 2NH₃(g)

When more and more H₂ gas is added, according to Le Chatelier's principle, the amount of ammonia keeps on increasing. Theoretically, the N₂ gas would not run out because the reaction is reversible.

When the balloon is squeezed into a smaller volume, the total pressure inside the balloon increases. Referring to the equation, there are 4 moles of gaseous molecules on the left, but 2 moles on the right. According to Le Chatelier's principle, the equilibrium position would shift to the right in order to reduce the number of gaseous molecules. Therefore, more N₂ gas and H₂ gas would react to give NH₃ gas.
2018-05-25 1:23 pm
Adding more hydrogen will produce more ammonia, until the nitrogen runs out.

When the volume decreases the equilibrium shifted toward the product, because there are only 2 moles of gaseous product, but there is a total of 4 moles of gaseous reactants.


收錄日期: 2021-04-24 01:05:46
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