Please hurry my teacher never taught this and I have finals 2 days from now.?

Refer to the diagram below.
The red dotted lines divide the square into 8 equal portions, and the shaded area occupies 5 portions.

Area of the square
= 2.5 ÷ (5/8) sq. units
= 2.5 × (8/5) sq. units
= 4 square units

Length of a side of the square
= √4 units
= 2 units

Diameter of the circle
= Diagonal of the square
= √(2² + 2²) units
= √8 units
= 2√2 units

Radius of the circle
= 2√2 / 2 units
= √2 units

Area of the circle
= π (√2)² sq. units
= 2π sq. units
≈ 2 × 3.14 sq. units
= 6.28 sq. units

The area of the shaded region is 2.5 square units.
The red dotted lines divide the square into 8 equal portions, and the
shaded area occupies 5 portions.

Area of one triangle = (5/2)/5 = 1/2
Area of square is 8(1/2) = 4
side of square ED is √4 = 2
half that, EF = 1
radius of circle CF is √2
.. from r² = 1² + 1²
diameter of circle is 2√2
area of circle is πr² = π(√2) = 2π

Area of the square
= 4 square units
Length of a side of the square
= 2 units
Diameter of the circle
= 2√2 units
Radius of the circle
= √2 units
Area of the circle
= 2π sq. units

From the given information, we have
2r^2=s^2------(1)
[s^2-(r^2)/2]/2+(r^2)/2=2.5=>
(s^2)/2+(r^2)/4=2.5=>
r^2+(r^2)/4=2.5 [from (1)]=>
5r^2=10=>
r^2=2=>
r=sqr(2) unit
The area of the circle=2pi unit^2
The area of the unshaped
part inside the square=
[s^2-(r^2)/2]/2=
[3r^2]/4=3/2 unit^2
The area of the circle outside
the square=
2pi-s^2=
2pi-2r^2=
2(pi-2) unit^2

The figure shows a square inscribed in a circle.
The area of the shaded region is 2.5 square units.
r^2 = 2.5
A = pi r^2 = = 7.853981633974483
The approximate area of the circle is 7.85 units^2.