What is the molarity of the HCl
solution?
Answer in units of M
Suppose that 17.04 mL of 0.468 M Ca(OH)2 is required to neutralize 13.7 mL of aqueous HCl solution.?
2018-05-16 11:22 am
回答 (1)
2018-05-16 12:07 pm
Ca(OH)₂(aq) + 2HCl(aq) → CaCl₂(aq) + 2H₂O(l)
Mole ratio Ca(OH)₂ : HC; = 1 : 2
No. of millimoles of Ca(OH)₂ reacted = (0.468 mmol/mL) × (17.04 mL) = 7.975 mmol
No. of millimoles of HCl required = (7.975 mmol) × (2/1) = 15.95 mmol
Molarity of HCl = (15.95 mmol) / (13.7 mL) = 1.16 M
Mole ratio Ca(OH)₂ : HC; = 1 : 2
No. of millimoles of Ca(OH)₂ reacted = (0.468 mmol/mL) × (17.04 mL) = 7.975 mmol
No. of millimoles of HCl required = (7.975 mmol) × (2/1) = 15.95 mmol
Molarity of HCl = (15.95 mmol) / (13.7 mL) = 1.16 M
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