How many milligrams of polonium-210 remain
after 553.6 days if you start with 8.3 mg
of the isotope?
Answer in units of mg
The half-life of polonium-210 is 138.4 days.?
2018-05-16 9:35 am
回答 (2)
2018-05-16 1:42 pm
Let n be the number of half-lives.
(1/2)ⁿ = 138.4/553.6
Mass of polonium remains = (8.3 mg) × (1/2)ⁿ = (8.3 mg) × (138.4/553.6) = 2.1 mg (to 2 sig. fig.)
(1/2)ⁿ = 138.4/553.6
Mass of polonium remains = (8.3 mg) × (1/2)ⁿ = (8.3 mg) × (138.4/553.6) = 2.1 mg (to 2 sig. fig.)
2018-05-17 3:09 am
use this equation
.. A(t) = A(o) * (1/2)^(time / half life)
so that
.. A(t) = 8.3mg * (1/2)^(553.6 days / 138.4 days) = 0.52mg
.. A(t) = A(o) * (1/2)^(time / half life)
so that
.. A(t) = 8.3mg * (1/2)^(553.6 days / 138.4 days) = 0.52mg
2018-05-16 9:41 am
553.6/138.4 = exactly 4, so you'll end up with
1/2 x 1/2 x 1/2 x 1/2 of the original amount;
you'll end up with 0.52 mg.
1/2 x 1/2 x 1/2 x 1/2 of the original amount;
you'll end up with 0.52 mg.
收錄日期: 2021-05-02 18:53:49
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20180516013519AAwtIXI