A proton has a charge of +1.6e-19 C.
An electron has a charge of -1.6e-19 C.
What is the force of repulsion between 2 protons if they are 3.4e-11 m apart?
Help pls with physics question?
2018-05-15 7:56 am
回答 (1)
2018-05-15 8:06 am
F = kq1q2/r^2
= (9.0 x 10^9 Nm^2/C^2)(-2.56 x 10^(-38) C^2)/(3.4 x 10^(-11) m)^2
= about 0.2 micronewtons, but use a calculator.
= (9.0 x 10^9 Nm^2/C^2)(-2.56 x 10^(-38) C^2)/(3.4 x 10^(-11) m)^2
= about 0.2 micronewtons, but use a calculator.
收錄日期: 2021-05-01 20:57:19
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