Prove these 2 triangles are similar?
回答 (3)
Q1.
AC is parallel to ED
R is a common point for the two given triangles.
Alternate angles and opposite angles are equal.
Hence the two triangles are similar.
Q2
C is common point.
BD is parallel to AE.
Angle A is common to both the triangles.
Angle A = Angle B and Angle D = Angle E.
Hence triangles ACE and BCD are similar.
=>
AC // ED...............given
∠ACB = ∠DEB................// lines alt. int. ∠s are =
∠ABC = ∠DBE...............vertical ∠s are =
ΔABC ~ ΔDEB ................AA similar
NOT visiting ANY site requiring registration and login. Post the question. Or don't bother.
收錄日期: 2021-04-24 01:07:04
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20180421175357AA0WZtt
檢視 Wayback Machine 備份