To test the flow of coolant through a radiator with a 2 in. diameter passage, a flow of 5 gal was recorded in 4 min. Velocity in ft/sec = ?
回答 (1)
5 gallons/4 min = v*pi*(1 in)^2 =>
v = (5 x 231 in^3)/[pi*(1 in)^2*60 s]
= 6.1275 in/s = 0.51 ft/s.
收錄日期: 2021-05-01 22:14:08
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20180418214925AA7QaBF
檢視 Wayback Machine 備份