若a<0,則y=ax+3,不通過第幾象限?

2018-04-16 8:31 pm

回答 (1)

2018-04-16 10:20 pm
若a<0,則y=ax+3,不通過第幾象限?
Sol
a<0
y=ax+3
x=0=>y=3 =>(0,3)=>(0,+)
y=0=>ax=-3=>x=-3/a=>(-3/a,0)=>(+,0)
(0,+),(+,0) 不通過第3象限


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