1. Find dy/dx if:
a. y = cos^-1(x) + sin^-1(x)
b. y = tan^-1 (e^2x)
c. y = cos(sin^-1(x))
Questions regarding Calculus Differentiation?
2018-04-13 1:52 pm
回答 (3)
2018-04-13 2:52 pm
One question per ticket please. I like the last one.
y = cos[sin⁻¹(x)]
dy/dx
= d/dx cos[sin⁻¹(x)]
= -sin[sin⁻¹(x)] d/dx[sin⁻¹(x)]
= (-x) [1 / √(1 - x²)]
= -x / √(1 - x²)
y = cos[sin⁻¹(x)]
dy/dx
= d/dx cos[sin⁻¹(x)]
= -sin[sin⁻¹(x)] d/dx[sin⁻¹(x)]
= (-x) [1 / √(1 - x²)]
= -x / √(1 - x²)
2018-04-13 2:00 pm
dy/dx = 867, 5309
收錄日期: 2021-05-01 22:27:59
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20180413055242AAliOjv